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Prove that $\log _a a=1$
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To prove that $\log_a a = 1$, we can use the definition of logarithms. A logarithm with base a is defined as the exponent to which a must be raised to give the number x.

Mathematically, if $y = log_a x$, then $a^y = x$.

So in this case, if we set $x = a$, we have: $a^{\log_a a} = a$

Because a raised to the power of $\log_a a$ is equal to $a$, then $\log_a a = 1$
by Diamond (88,832 points)

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