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Determine the expression for the nth term


in Mathematics by (108 points)
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Given the sequence \(20;17;14;\ldots -103 \dots\) it can be seen that the common difference is \(-3\) i.e. \(a_{n+1}-a_n=3\)




This is a decreasing sequence i.e. decreasing by 3 with each term.

the fourth term is calculated using the following linear equation:



\[\therefore a_4=11\]

by Platinum (118,860 points)
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The nth term is given by the formula:

\[T_n=a+(n-1) d\]


\(a\) is the first term

\(d\) is the common difference

\[T_n = 20+(4-1)-3\]

\[T_n =20-9=11\]
by Gold Status (30,709 points)

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