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If \(a^{2}+b^{2}+a b=11^{2}\)
\(b^{2}+c^{2}+b c=13^{2}\)
\(c^{2}+a^{2}+c a=20^{2}\)
where \(a, b, c \in \mathbb{R}^{+}\)
Then the value of
\[
a b+b c+c a
\]
is
a. 150
b. \(88 \sqrt{3}\)
c. \(66 \sqrt{5}\)
d. 120
in Mathematics by Gold Status (30,625 points) | 37 views

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