Answer:
\[
x=1+\frac{\sqrt{7}}{2} \text { or } x=1-\frac{\sqrt{7}}{2}
\]
Explanation:
\(4 x^{2}-8 x-3=0\)
Identify the coefficients
\(a^{-4}, b=-8, c=-3\)
Substiture the values into the quadratic formula
\[
x=\frac{-(-8)+\sqrt{(-8)^{2}-4 \times 4 \times(-3)}}{2 \times 4}
\]